Closed ldworkin closed 7 years ago
Previously, we had an issue with things like nthRoot(x)(1+2). This would be parsed incorrectly, whereas nthRoot(x) * (1+2) would be fine. They should really be the same. This fix simply converts the former to the latter.
nthRoot(x)(1+2)
nthRoot(x) * (1+2)
See broken example:
Previously, we had an issue with things like
nthRoot(x)(1+2). This would be parsed incorrectly, whereasnthRoot(x) * (1+2)would be fine. They should really be the same. This fix simply converts the former to the latter.See broken example: