Open hey-monster opened 4 years ago
Implement pow(x, n), which calculates x raised to the power n (xn).
Example 1:
Input: 2.00000, 10 Output: 1024.00000 Example 2:
Input: 2.10000, 3 Output: 9.26100 Example 3:
Input: 2.00000, -2 Output: 0.25000 Explanation: 2-2 = 1/22 = 1/4 = 0.25 Note:
-100.0 < x < 100.0 n is a 32-bit signed integer, within the range [−231, 231 − 1]
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/powx-n 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
思路一:
不好意思了,没注意把原来的issue内容给改掉了
@hey-monster I would like to work on this.
Implement pow(x, n), which calculates x raised to the power n (xn).
Example 1:
Input: 2.00000, 10 Output: 1024.00000 Example 2:
Input: 2.10000, 3 Output: 9.26100 Example 3:
Input: 2.00000, -2 Output: 0.25000 Explanation: 2-2 = 1/22 = 1/4 = 0.25 Note:
-100.0 < x < 100.0 n is a 32-bit signed integer, within the range [−231, 231 − 1]
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/powx-n 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
思路一: