Open gserdyuk opened 12 years ago
Lets take system:
[ gmin -1 ] * X = [ -1 ] 10 -10 0
if gmin = 0 this system has exact solution X= 1; 1
but current solver behaves wrong (gives X= {1.0} ) in wide range of gmin.
shortly : if gmin <=1.e-17 solver returns X={0, 1} if gmin = 1e-6 X={1,1} (correct)
pls see attached a) circuit file with test ckt b) test functiion for "boost test"
now can use current solver, keep in mid that gmin ~ 1.e-6
in future - substitute linear solver with another one.
circuit file for test:
I1 1 0 dc 0 G11 1 0 1 0 -10 G12 1 0 2 0 +10
G21 2 0 1 0 -1 I2 2 0 dc 1
.print op v(1) v(2) i(i1) i(i2) .op .end
low priority as quite artificial circuit
Lets take system:
[ gmin -1 ] * X = [ -1 ] 10 -10 0
if gmin = 0 this system has exact solution X= 1; 1
but current solver behaves wrong (gives X= {1.0} ) in wide range of gmin.
shortly : if gmin <=1.e-17 solver returns X={0, 1} if gmin = 1e-6 X={1,1} (correct)
pls see attached a) circuit file with test ckt b) test functiion for "boost test"
now can use current solver, keep in mid that gmin ~ 1.e-6
in future - substitute linear solver with another one.