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h-Klok / StatsWithJuliaBook

https://statisticswithjulia.org/
MIT License
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subtype() should be subtypes() #23

Closed jkort closed 3 years ago

jkort commented 3 years ago

In section 1.1:

...while the functions subtype() and supertype() return the subtype and supertype of a particular type respectively...

I believe the correct function name is subtypes() <-- plural

yoninazarathy commented 3 years ago

Fixed, thank you.