Closed hawkrives closed 9 years ago
Memoization caches the outputs of a function call, linked to the input.
So when you call a function a second time, with the same input, it can just return the already-computed result.
Memoization caches the outputs of a function call, linked to the input.
So when you call a function a second time, with the same input, it can just return the already-computed result.