element index incorrect for equal XML elements with same parent

[haysclark]

From tra...@circutus.com on October 05, 2011 09:55:41

Given two identical

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elements, with the same parent node, calling XPathUtils.findPath(to, from, context) will always return an xpath expression pointing to the same

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node index.

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text

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The reason is because XPathUtils function getPeerPositionPredicate(node, context) compares the contents of XML elements to determine the node index. Instead, it should compare the "childIndex" of the XML element.

Here's a fixed version of the function:

private static function getPeerPositionPredicate(node:XML, context:XPathContext):String { var parent:XML = node.parent(); if(!parent){ return ""; }

var peers:XMLList = node.parent()[node.name()]; var n:int = peers.length(); var i:int = 0; if (n > 1){ var nodeIndex:int = node.childIndex(); for(; i < n; ++i){ if (nodeIndex == peers[i].childIndex()) break; } } return "[" + (context.zeroIndexPosition ? i : ++i) + "]"; }

Original issue: http://code.google.com/p/xpath-as3/issues/detail?id=26

[haysclark]

From peterj...@gmail.com on August 27, 2012 21:31:41

Hi Travis, I've committed the fix and made a new build. Apologies for the delay, I wasn't getting notifications on new issues.

Status: Fixed