about 扩展函数不能被override

[spff]

這樣算是可以被override嗎

class Inner{
}

open class Parent{
    open fun Inner.extendFunc3():String = ""
}

class Child:Parent(){
    override fun Inner.extendFunc3():String = "override"
}

[Cat7373]

并不算，有多个同名的扩展函数时，哪个在上下文中哪个就生效，并没有覆盖关系

[spff]

In Java, all non-static methods are by default "virtual functions." Only methods marked with the keyword final, which cannot be overridden, along with private methods, which are not inherited, are non-virtual.

能否override取決於是否為virtual ，然後上面的code轉成Java並沒看到static 或 final (不過我無法使用super來呼叫Parent寫的Inner.extendFunc3就是了)

[spff]

看了kotlin官網寫的大概知道tip4原本想表達的意思，不過覺得用官網的例子會更好懂一些 C().caller(D()) // prints "D.foo in C" C1().caller(D()) // prints "D.foo in C1" - dispatch receiver is resolved virtually C().caller(D1()) // prints "D.foo in C" - extension receiver is resolved statically

然後究其原因是因為在轉換的時候會overload成兩個function

   public void foo(@NotNull D $receiver) {
      Intrinsics.checkParameterIsNotNull($receiver, "$receiver");
      String var2 = "D.foo in C";
      System.out.println(var2);
   }

   public void foo(@NotNull D1 $receiver) {
      Intrinsics.checkParameterIsNotNull($receiver, "$receiver");
      String var2 = "D1.foo in C";
      System.out.println(var2);
   }

[heimashi]

@spff 感谢反馈，之前的表意的确有些不够恰当，已更新