Closed marcwrobel closed 1 year ago
If f = x => x + 1 and g = x => x * 2, then some(1).map(x => g(f(x))) = g(1 + 1) = (1 + 1) * 2 = 4.
f = x => x + 1
g = x => x * 2
some(1).map(x => g(f(x))) = g(1 + 1) = (1 + 1) * 2 = 4
See also #238.
If
f = x => x + 1andg = x => x * 2, thensome(1).map(x => g(f(x))) = g(1 + 1) = (1 + 1) * 2 = 4.See also #238.