'Decode' function for python doesn't have 'precision' parameter

[alexisad]

Regarding this: https://developer.here.com/documentation/here-lanes/dev_guide/topics/hd-map-coordinate-encoding.html Platform data topologies have 7 digits of precision after the decimal point. But decode function by default returns only 5 digits after the decimal point.

Please add 'precision' parameter in the 'decode' function. Thanks

[gtsystem]

The decoded precision depends on the precision used when encoding the polyline. The encoder has a default of 5 digits of precision but there is a parameter to change that:

import flexpolyline as fp
input = [
    (50.1022829, 8.6982122),
    (50.1020076, 8.6956695),
    (50.1006313, 8.6914960),
    (50.0987800, 8.6875156),
]
res = fp.encode(input, precision=7)
print(fp.decode(res))

Output:

[(50.1022829, 8.6982122), (50.1020076, 8.6956695), (50.1006313, 8.691496), (50.09878, 8.6875156)]

[frankgae]

I recommend to close this feature request.

1. As Giuseppe commented, the number of available decimals depends on the precision specified during encoding, not the decoding.
2. "Reducing" the precision of the decoded coordinates is basically a 1-liner in Python. e.g:

       pts = fp.decode(s)
       pts = [(round(lat, 3), round(lng, 3)) for lat, lng in pts]

   This doesn't justify adding 'precision' and 'precision3d' arguments to the 'decode' method.