Closed morgenst closed 8 years ago
Sorry folks, somehow missed issue #276. Anyhow, is there any explanation why it works with sqrt from numpy and not with scipy implementation? Thx
Thanks for your comments about Pint! We are glad that you find it useful.
It works for numpy because numpy provides a hook to provide custom implementations for numerical functions. This is not the case for scipy. By the way for your case, you can just do:
>>> (q1 ** 2 + q2 ** 2) ** (1./2)
Hi dev team,
let me first stress that pint is a very awesome tool I enjoy much using. However, I came across an issue when doing quadratic uncertainty propagation. Essentially when I do the following:
`from scipy import sqrt ureg = pint.UnitRegistry()
q1 = ureg.Quantity(10, ureg.Bq) q2 = ureg.Quantity(10000, ureg.mBq) q3 = sqrt(pow(q1,2) + pow(q2, 2))'
the magnitude is calculated correctly, but q3 is dimensionless. Since this is a quite often occuring calculation in physics, I was wondering whether there is a fix for this?
Thanks, Marcus