Open robertHowlett opened 1 month ago
def some_func(): foo = ( [ [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3], [ 1, 2, 3]])
When I run autopep8, it seems to think that this is correct formatting. I expect the indent of every row to be the same, and for each row of the data to begin with an open square bracket.
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$ autopep8 --diff --max-line-length=120 path/to/file.py
Python Code
When I run autopep8, it seems to think that this is correct formatting. I expect the indent of every row to be the same, and for each row of the data to begin with an open square bracket.
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