The formula states
$$\sum{i=0}^{n}{(2n+1)} = n^2$$
Which is false for many examples. The statement in lean induces it to actually be
$$\sum{i=0}^{n-1}{(2i+1)} = n ^2$$
I would change it myself and open a PR, but I couldn't find where it is defined in the repo.
In the 4th level of Babylon:
The formula states $$\sum{i=0}^{n}{(2n+1)} = n^2$$ Which is false for many examples. The statement in lean induces it to actually be $$\sum{i=0}^{n-1}{(2i+1)} = n ^2$$ I would change it myself and open a PR, but I couldn't find where it is defined in the repo.