Closed PayneTrain closed 11 years ago
Very helpful
Basically just place a diode in series with each battery to keep a voltage difference between dead and charged battery from creating a huge spike in current
Looking into this chip
Emailed Linear Technologies (didn't respond to my call) looking for a simple diode (rather than a embedded 2-channel system that would need a controller input)
lets make sure this doesn't happen :+1: https://www.youtube.com/watch?v=B-AoAYrEy-o
Bought these diodes (will chain two) see the below email from linear:
No micro required with LTC4414. It also withstands -14V. If you need more protection, use this: http://cds.linear.com/docs/en/application-note/an107f.pdf
The LTC4414 should be perfect for this project. They will probably need to use 2 back-to-back FETs for each battery channel. In this case, the “Aux” power is the “primary” battery.
Regards,
This is the circuit, just working with LTC to get the right external PMOSs (x2) and then PCBExpress to get our circuit boards.
@towlett I'm planning to have the new circuit layout to you by Saturday, does that work for you in terms of creating the new middle plate?
Sure that works. As long as we have all the components so that I can measure holes, I can update the middle plate and get it done over break or immediately afterwards.
The board should be here Friday unfortunately I'll be gone at noon so will have to install it Sunday Night/Monday:
I'm closing this issue now but if we choose to do another iteration of the board (~$60) then I would try to add a power switch and Tamiya connectors as found on the EduBot.
The red is what is visible to the user:
Drawing from the UPenn "Technical Paper" in the repo, implement a logical OR that allows us to swap out a dying battery with a fresh one without causing the system to lose power.