Question on VectorPtrView

[nehcuh]

Sorry to reopen this question.

Let's assume that we've constuct a VectorPtrView of a vector, then, using method of VectorPtrView such as at, [], which would may result in errors. The method of at which I quote your realization here

inline reference at(sizetype n) { return (*(vector[n])); } is not to give the element of the Vector, instead, it's assuming the element is a pointer.

Is there any misunderstanding?

Also, is VectorPtrView lack of realization of operator '!=' and '>'?

[hosseinmoein]

The whole point of view vector objects is to have references (not copies) to an original data vector. So the view vector content is always pointers

[nehcuh]

    inline VectorPtrView(const std::vector<T> &rhs)  { *this = rhs; }
    inline VectorPtrView(std::vector<T> &rhs)  { *this = rhs; }

Such codes mean VectorPtrView will hold pointer of rhs? Sorry for my bad cpp program skill and a lot of thanks for your patience!

[hosseinmoein]

Yes. they are defined in these operators

inline VectorPtrView &operator = (const std::vector<T> &rhs)
inline VectorPtrView &operator = (std::vector<T> &rhs)

[nehcuh]

Thanks! 😄