Printf is not handling some format specifiers correctly

[rebeccabuckingham]

Noticed with %ld and %lu:

` long x = 1984;

// this prints 'x is %ld', the value of x isn't substitued in the string // removing the 'l' will result in a compiler warning // "format specifies type 'int' but the argument has type 'long'" printf("x is %ld\n", x);

unsigned long y = 9000;

// this prints 'y is %lu', the value of y isn't substituted in the string. // removing the 'l' will result in a compiler warning. printf("y is %lu\n", y);`

[hth313]

You might need to switch to another printf formatter, see section "16.6 Library on a diet" in the user guide. Another thing that can go wrong with printf is that it uses more stack than some other routines, so you may need to ensure to increase it.

[ProxyPlayerHD]

damn i had no idea that was even an option, i thought float support and such simply didn't exist at all.

though i feel like there should be a warning/message about that from the compiler if you use one of the optional formatting characters like. so for example when you use %f it would tell you that you also need to have --rtattr printf=float in the linker command for that to actually work, and that it will increase code size.

[hth313]

Yeah, I can add it to the list of things to do. At least when the formatter string is known it could automatically pick the smallest working formatter.