Open huimeich opened 5 years ago
def __init__(self):
"""
Initialize your data structure here.
"""
self.stack = []
self.idict = {}
def insert(self, val: int) -> bool:
"""
Inserts a value to the set. Returns true if the set did not already contain the specified element.
"""
if val in self.idict:
return False
self.stack.append(val)
self.idict[val] = len(self.stack) - 1
return True
def remove(self, val: int) -> bool:
"""
Removes a value from the set. Returns true if the set contained the specified element.
"""
if val in self.idict:
i = self.idict[val]
del self.idict[val]
if i != len(self.stack) - 1:
self.stack[i] = self.stack[-1]
self.idict[self.stack[i]] = i
self.stack.pop()
return True
return False
def getRandom(self) -> int:
"""
Get a random element from the set.
"""
return self.stack[random.randint(0, len(self.stack) - 1)]
Design a data structure that supports all following operations in average O(1) time.
insert(val): Inserts an item val to the set if not already present. remove(val): Removes an item val from the set if present. getRandom: Returns a random element from current set of elements. Each element must have the same probability of being returned. Example:
// Init an empty set. RandomizedSet randomSet = new RandomizedSet();
// Inserts 1 to the set. Returns true as 1 was inserted successfully. randomSet.insert(1);
// Returns false as 2 does not exist in the set. randomSet.remove(2);
// Inserts 2 to the set, returns true. Set now contains [1,2]. randomSet.insert(2);
// getRandom should return either 1 or 2 randomly. randomSet.getRandom();
// Removes 1 from the set, returns true. Set now contains [2]. randomSet.remove(1);
// 2 was already in the set, so return false. randomSet.insert(2);
// Since 2 is the only number in the set, getRandom always return 2. randomSet.getRandom();