Can I split 1 chain into #n rows of Panels ?

[GeorgeFlorian]

Hello !

I am currently using a Raspberry Pi Zero W V1.1. I am using it just to test things out until I get my hands on a Raspberry Pi 2 or 3.

I am using 64x32 1/8 Outdoor SMD P5 2727 LED Panels.

I am trying to have 60 LED Panels arranged as follows:

_P6_P5_P4_P3_P2_P1_Chain1_RaspBerryPi1
P11_P10_P9_P9_P8_P7_
_P6_P5_P4_P3_P2_P1_Chain2_RaspBerryPi1
_P11_P10_P9_P9_P8_P7
_P6_P5_P4_P3_P2_P1_Chain3_RaspBerryPi1
_P11_P10_P9_P9_P8_P7
_P6_P5_P4_P3_P2_P1_Chain1_RaspBerryPi2
_P11_P10_P9_P9_P8_P7
_P6_P5_P4_P3_P2_P1_Chain2_RaspBerryPi2
_P11_P10_P9_P9_P8_P7

Basically 10 rows with 6 panels each. My question is how can I make 1 chain to be on 2 rows and how can I tell one row to be 6 displays in length ?

Until now I've linked 4 displays in 1 chain on 1 row. How can I tell this chain to be on 2 rows and to be 2 panels in length ?

One last question: is it possible to have the above arrangement run by a single Raspberry Pi ?

This would mean 2 chains with 30 panels each.

_P6_P5_P4_P3_P2_P1_Chain1_RaspBerryPi1
_P11_P10_P9_P9_P8_P7_
_P17_P16_P15_P14_P13_P12_
_P23_P22_P21_P20_P19_P18_
P29_P28_P27_P26_P25_P24_
_P6_P5_P4_P3_P2_P1_Chain2_RaspBerryPi1
_P11_P10_P9_P9_P8_P7_
_P17_P16_P15_P14_P13_P12_
_P23_P22_P21_P20_P19_P18_
P29_P28_P27_P26_P25_P24_

[Beersatron]

I think you will need a Raspberry Pi 3 for this. I created a scoreboard that has 12 64x32 panels in two parallel chains.

My cmd is:

sudo /home/pi/rpi-rgb-led-matrix/examples-api-use/scoreboard -f /home/pi/rpi-rgb-led-matrix/fonts/10x20.bdf --led-pixel-mapper="U-mapper" --led-rows=32 --led-cols=64 --led-chain=6 --led-parallel=2 --led-show-refresh --led-slowdown-gpio=2 --led-pwm-dither-bits=2

This is the part that makes 6 chained panels into "2 rows of 3 panels": --led-pixel-mapper="U-mapper" --led-chain=6

[GeorgeFlorian]

I think you will need a Raspberry Pi 3 for this. I created a scoreboard that has 12 64x32 panels in two parallel chains.

My cmd is:

sudo /home/pi/rpi-rgb-led-matrix/examples-api-use/scoreboard -f /home/pi/rpi-rgb-led-matrix/fonts/10x20.bdf --led-pixel-mapper="U-mapper" --led-rows=32 --led-cols=64 --led-chain=6 --led-parallel=2 --led-show-refresh --led-slowdown-gpio=2 --led-pwm-dither-bits=2

This is the part that makes 6 chained panels into "2 rows of 3 panels": --led-pixel-mapper="U-mapper" --led-chain=6

Thank you for your answer.

For 6 panels on one row I will use the following, correct ?

--led-pixel-mapper="U-mapper" --led-rows=32 --led-cols=64 --led-chain=12 --led-parallel=3

Basically, with this I can split one chain just once, resulting in 3 chains with 12 panels each that will be split just once using the U-map. This means 36 panels.

I need 10 rows with 6 panels each, so 60 panels. This would mean that I will need a second Raspberry Pi 3 with another 2 chains with 12 panels each, for a total of 10 rows.

But can I compose the final image using two separate Raspberries ?

Also, is there any way I can use just one Raspberry ?

_P6_P5_P4_P3_P2_P1_Chain1_RaspBerryPi1
_P11_P10_P9_P9_P8_P7_
_P17_P16_P15_P14_P13_P12_
_P23_P22_P21_P20_P19_P18_
P29_P28_P27_P26_P25_P24_
_P6_P5_P4_P3_P2_P1_Chain2_RaspBerryPi1
_P11_P10_P9_P9_P8_P7_
_P17_P16_P15_P14_P13_P12_
_P23_P22_P21_P20_P19_P18_
P29_P28_P27_P26_P25_P24_

[<][<][<][<][<][<]-Chain1_RaspBerryPi1
[>][>][>][>][>][>]
[<][<][<][<][<][<]
[>][>][>][>][>][>]
[<][<][<][<][<][<]
[>][>][>][>][>][>]-Chain2_RaspBerryPi1
[<][<][<][<][<][<]
[>][>][>][>][>][>]
[<][<][<][<][<][<]
[>][>][>][>][>][>]

I would need to split 1 chain 4 times to make it into 5 rows of panels. How can I translate that into a cmd ?

--led-rows=32 --led-cols=64 --led-chain=30 --led-parallel=2 --led-pixel-mapper="S-shape"

Or maybe 3 chains:

_P6_P5_P4_P3_P2_P1_Chain1_RaspBerryPi1
_P11_P10_P9_P9_P8_P7_
_P17_P16_P15_P14_P13_P12_
P23_P22_P21_P20_P19_P18_
_P6_P5_P4_P3_P2_P1_Chain2_RaspBerryPi1
_P11_P10_P9_P9_P8_P7_
_P17_P16_P15_P14_P13_P12_
P23_P22_P21_P20_P19_P18_
_P6_P5_P4_P3_P2_P1_Chain3_RaspBerryPi1
_P11_P10_P9_P9_P8_P7_

How would the cmd look like ? I would be Chain 1 in an S-mapping, Chain 2 also in an S-mapping and Chain 3 in U-mapping

[<][<][<][<][<][<]-Chain1_RaspberryPi1
[>][>][>][>][>][>]
[<][<][<][<][<][<]
[>][>][>][>][>][>]
[<][<][<][<][<][<]-Chain2_RaspberryPi2
[>][>][>][>][>][>]
[<][<][<][<][<][<]
[>][>][>][>][>][>]
[<][<][<][<][<][<]-Chain3_RaspberryPi2
[>][>][>][>][>][>]

In this case I would need a way of choosing the mapping for each chain separately.

[angelogoncalve]

see this link and the issue: https://github.com/hzeller/rpi-rgb-led-matrix/pull/611

https://github.com/t413/rpi-rgb-led-matrix/tree/s-mapper

flag:

--led-pixel-mapper="S-mapper"

other way see this issue:

https://github.com/hzeller/rpi-rgb-led-matrix/issues/341

[shanerooni]

I think you will need a Raspberry Pi 3 for this. I created a scoreboard that has 12 64x32 panels in two parallel chains.

My cmd is:

sudo /home/pi/rpi-rgb-led-matrix/examples-api-use/scoreboard -f /home/pi/rpi-rgb-led-matrix/fonts/10x20.bdf --led-pixel-mapper="U-mapper" --led-rows=32 --led-cols=64 --led-chain=6 --led-parallel=2 --led-show-refresh --led-slowdown-gpio=2 --led-pwm-dither-bits=2

This is the part that makes 6 chained panels into "2 rows of 3 panels": --led-pixel-mapper="U-mapper" --led-chain=6

@Beersatron , I'm trying to also create a 12 panel 64x32 display. would you be able to walk me through some pointers? if possible, you can email me using the email on my profile. thanks!