Closed Andykwan123 closed 2 years ago
No. For each grid cell, the values of vertices should between 0 and 1. However, the values of vertices are accumulated from its neighboring grid cells.
so the values of vertices are not divided by N (vi). If so how do I know the number of N(vi)? thank you!
You can know it according to its coordinates. For example, N(vi) = 0 for (0, 0, 0) and N(vi) = 8 for (15, 15, 15)
So the returned grid is not divided by N(vi) ?(which called the value of vertices)
If I want to know the value of wi, in addition to knowing the neighbor points of each vertex, is there a variable about wi that can be printed out in the program?
Thanks for your reply!
No. I don't create a variable for that because I didn't use it.
I used the command to display the value of the grid, and observed that many values will be greater than 1, which is different from (2) in the paper, I think N (vi) is not divided to cause w to be greater than one, or am I misunderstand about (2) (I think its value will be between 0~1)?