Open goldsztejn-a opened 1 year ago
ibexopt answers infeasible to the following minibex. I agree that x^0 is a strange way to encode 1, but this is correct.
Variables x in [-1 , 1];
Minimize x^0 + x^1;
Constraints end
ibexopt answers infeasible to the following minibex. I agree that x^0 is a strange way to encode 1, but this is correct.
Variables x in [-1 , 1];
Minimize x^0 + x^1;
Constraints end