Implement the ability to deserialize into an existing object.
Foo f = new Foo();
Serializer s = new Serializer(typeof(Foo));
s.Deserialize("{ Bar: 1 }", f);
// Prints "1"
Console.WriteLine(f.Bar);
Original issue reported on code.google.com by elliott....@gmail.com on 4 Oct 2009 at 2:38
Original issue reported on code.google.com by
elliott....@gmail.com
on 4 Oct 2009 at 2:38