Open weerox opened 4 years ago
I think that if you have no gate tool selected (n) should give you a not-gate from the get go.
Yeah, 👍
If the NOT-tool is selected, should (a) produce a NAND then?
Not sure about that as it might be too contextual, but we could try implementing it and seeing how confusing or not it is.
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The gates can be negated (Not, Nand, Nor, Xnor) by (n).