Closed cliff0412 closed 1 year ago
rob is reversed-bit-order 'd11 = 'b1011 so rob('b1011) = 'b(1101) = 'd13
thanks for the explanation. for example, if it is 4 bits number, then it will access {0,8,4,12,2,10,6,14} and then {1,9,5,13,3,11,7,15}. the even and odd cosets alright? and the order does not matter?
exactly. also, if you want cosets of order 4 you'll have {0,8,4,12}, {2,10,6,14}, etc
Refer to paper A Mathematical Theory of Danksharding.
in this definition u_{\mu} \equiv u^{rbo(\mu)}
how to understand rbo?
for example, what would the output of rbo(11) be?