When I clicked run after I had done what I needed to I got this error message:
Traceback (most recent call last):
File "client3.py", line 34, in
quotes = json.loads(urllib.request.urlopen(QUERY.format(random.random())).read())
File "/usr/lib/python3.8/urllib/request.py", line 222, in urlopen
return opener.open(url, data, timeout)
File "/usr/lib/python3.8/urllib/request.py", line 525, in open
response = self._open(req, data)
File "/usr/lib/python3.8/urllib/request.py", line 542, in _open
result = self._call_chain(self.handle_open, protocol, protocol +
File "/usr/lib/python3.8/urllib/request.py", line 502, in _call_chain
result = func(*args)
File "/usr/lib/python3.8/urllib/request.py", line 1383, in http_open
return self.do_open(http.client.HTTPConnection, req)
File "/usr/lib/python3.8/urllib/request.py", line 1357, in do_open
raise URLError(err)
urllib.error.URLError: <urlopen error [Errno -2] Name or service not known>
KeyboardInterrupt
Hi all,
When I clicked run after I had done what I needed to I got this error message:
Traceback (most recent call last): File "client3.py", line 34, in
quotes = json.loads(urllib.request.urlopen(QUERY.format(random.random())).read())
File "/usr/lib/python3.8/urllib/request.py", line 222, in urlopen
return opener.open(url, data, timeout)
File "/usr/lib/python3.8/urllib/request.py", line 525, in open
response = self._open(req, data)
File "/usr/lib/python3.8/urllib/request.py", line 542, in _open
result = self._call_chain(self.handle_open, protocol, protocol +
File "/usr/lib/python3.8/urllib/request.py", line 502, in _call_chain
result = func(*args)
File "/usr/lib/python3.8/urllib/request.py", line 1383, in http_open
return self.do_open(http.client.HTTPConnection, req)
File "/usr/lib/python3.8/urllib/request.py", line 1357, in do_open
raise URLError(err)
urllib.error.URLError: <urlopen error [Errno -2] Name or service not known>
KeyboardInterrupt
Does anyone know what this means?
Here's a screenshot of my current code: