Open mauriciosoares opened 8 years ago
I believe there is a getRawValue()
that will get you something close to that.
thanks @iamdustan
yes, getRawValue
would return in the previous example 111
.
But I do need the mask, but I need only the ones that are to the left of my last character, that's why in my example I get only one /
. The number of characters retrieved does matter for my case...
the getValue
would return a string with a length of 10. (even if I paste only a 111
)
the getRawValue
would return a string with a length of 3.
My example returns a string with a length of 4.
Just to let you know, I achieved this by doing some crazy hack, here's the snippet:
var instance = new InputMask({pattern: mask, value});
value.split('').forEach(s => instance.input(s));
const {end} = instance.selection;
return instance.getValue().slice(0, end);
Basically, I manually input
each of the characters in the instance (had to use input
instead of paste
, if 1 single character is wrong in the paste
method, it just dont paste
anything);
After that I get the end
property from the selection
object, and slice
the getValue
value from 0 to the end
number.
Still I'd like to know if there's a better approach :)
Hey, the title might seem a little confusing, but an example can make it very clear. Let's say I have the following pattern:
If I use the
getValue
method, I get the string'11/1_/____'
.Is there a way to get only the characters from the last 1 to the left? it would return something like this:
11/1
thanks.