StopIteration Error for python >= 3.5

[SufferProgrammer]

hi i wonder i could get answer about my error ASAP. so i wondering around google and not found anything like this error it's only mentioning about not connect with socket.io server, connection refused, and etc. and no thing i found like mine. i wonder if this socketIO-client is not support for python version 3.5+, or there any possibility that make my code error ?

here the error trace i get Traceback (most recent call last): File "clienio.py", line 10, in <module> socketIO = SocketIO('localhost', 5002, LoggingNamespace) File "/usr/local/lib/python3.5/dist-packages/socketIO_client-0.7.2-py3.5.egg/socketIO_client/__init__.py", line 353, in __init__ resource, hurry_interval_in_seconds, **kw) File "/usr/local/lib/python3.5/dist-packages/socketIO_client-0.7.2-py3.5.egg/socketIO_client/__init__.py", line 54, in __init__ self._transport File "/usr/local/lib/python3.5/dist-packages/socketIO_client-0.7.2-py3.5.egg/socketIO_client/__init__.py", line 62, in _transport self._engineIO_session = self._get_engineIO_session() File "/usr/local/lib/python3.5/dist-packages/socketIO_client-0.7.2-py3.5.egg/socketIO_client/__init__.py", line 76, in _get_engineIO_session transport.recv_packet()) StopIteration DEBUG:socketIO-client:localhost:5002/socket.io [socket.io disconnect]

and here my code import logging from socketIO_client import SocketIO, LoggingNamespace

def on_aaa_response(*args): print('on_aaa_response', args)

logging.getLogger("requests").setLevel(logging.WARNING) logging.basicConfig(level=logging.DEBUG)

socketIO = SocketIO('localhost', 5002, LoggingNamespace) socketIO.on("data", on_aaa_response) socketIO.wait(seconds=1)

thank you for advise

[markw63]

You are trying to connect to a client at 5002. And you got a disconnect packet. (which is an Error in SocketIO-client sometimes sadly, dependent on the type of disconnect)- a ConnectionError I think. you need to trap that with try: . I use this client with Python3.5 and 3.6 so it is not a version issue. The code you are using seems confused? You are mixing structures. socketIO is your SocketIO object from the class SocketIO.

socketIO.on("data",....) tells your socketIO class to trap the "data" event and tells it to call the function on_aaa_response. But, the way you have coded, on_aaa_response in the class will ALSO respond to a message type "aaaresponse". ie EITHER use socketIO.on(<"messagetype">, function to call) format or the on format Messages only arrive when you run SocketIO.wait(timeout), and then trigger the various functions you have setup

eg inside a class subclassed from BaseNamespace class Watchmsg(BaseNamespace):

    def on_connect(self):
        # handles connect messages  
   def on_myownmessage(self,*args):
      # handles messages that are socket.io.emit("myownmessage",somedata)

The point is that the documentation is giving you snippets and expecting you to put your own classes/structures around it. socketIO=SocketIO('localhost',port) mysio=socketIO.define(Watchmsg,"/mynamespacename") # sets up a namespace around the socketIO as mysio.

now for that namespace, add an event called messagename and an function call for action mysio.on("messagename",action)

works as does the way I did it above - setting functions with the prefix on_ in the body of the wrapping class.

HTH After that , see if you get errors and put some try: except: around the SocketIO.wait()

try:
    socketIO.wait(.5)

except ConnectionError as ex: print("got connection error")

You have to import ConnectionError from SocketIO if you want it.

[MisterWil]

This is an issue with this client library connecting to a Socket IO 2.0 server. See issue #155 and pull request #158 which successfully fixes the issue.