ERROR: Internal Python error in the inspect module.

[femibyte]

Hi, I'm using iPython 0.13 and got the following error:

In [109]: run gaussElim.py

In [110]: slv(B,b)

Traceback (most recent call last): File "/Library/Python/2.7/site-packages/ipython-0.13-py2.7.egg/IPython/core/ultratb.py", line 756, in structured_traceback records = _fixed_getinnerframes(etb, context, tb_offset) File "/Library/Python/2.7/site-packages/ipython-0.13-py2.7.egg/IPython/core/ultratb.py", line 242, in _fixed_getinnerframes records = fix_frame_records_filenames(inspect.getinnerframes(etb, context)) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/inspect.py", line 1035, in getinnerframes framelist.append((tb.tb_frame,) + getframeinfo(tb, context)) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/inspect.py", line 999, in getframeinfo lines, lnum = findsource(frame) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/inspect.py", line 578, in findsource if pat.match(lines[lnum]): break IndexError: list index out of range ERROR: Internal Python error in the inspect module. Below is the traceback from this internal error.

Unfortunately, your original traceback can not be constructed.

Here is my code (gaussElim.py):

from numpy import *

def slu(A1):

square LU factorization with no row exchanges

A=matrix(A1)
(n,n)=shape(A)
L=matrix(zeros((n,n)))
U=matrix(zeros((n,n)))
tol=1.e-6
for k in range(n):
    if abs(A[k,k]) < tol:
        return
    L[k,k]=1
    print "L=" + str(L)
    for i in range(k+1, n):   # Multipliers for column k are put into L
        L[i,k]=A[i,k]/A[k,k]
        for j in range(k, n): #Elimination beyond row k and column k
            A[i,j]=A[i,j]-L[i,k]*A[k,j]  # Matrix still called A
    for j in range(k-1, n):
        U[k,j]=A[k,j]
return(L,U)

def slv(A1,b1):

Solve Ax=b using L & U from slu(A). No row exchanges !!

[L,U]=slu(A)
(n,n)=shape(A)
c=zeros(n)
x=zeros(n)
s=0
for k in range(n):
    for j in range(k-1):
        s=s+L[k,j]_c[j]
    c[k]=b[k]-s    #Forward elimination to solve Lc=b
for k in range(n-1,-1,0): #Going backwards from x(n-1) to x(0) 
    for j in range(k+1,n):
        t=t+U[k,j]_x[j]
    x[k]=(c[k]-t)/U[k,k]
x=transpose(x)
return x

A=mat([[2,1],[6,8]]

run gaussElim.py

slu(A)

B=mat([[1,2],[4,9]])

b=array([5,21])

slv(B,b)

[takluyver]

Thanks. I think this is the same as #1456, which should have been fixed by PR #2232. The fix will be in 0.14.

[takluyver]

(Feel free to reopen if you can reproduce the error on master)

[femibyte]

Ok, thanks. When is 0.14 supposed to be released?

[takluyver]

There's no date set yet, but probably around the end of the year.

[xgdgsc]

When is 0.14 supposed to be released?

[minrk]

1.0 will be released in July.

[isghost]

I'm using Ipython 2.3.1,if path including chinese,will get this error