regex.search("([\da-f:]+)$", "E", regex.I|regex.V1) returns None

What steps will reproduce the problem?
Python 3.2.2 (default, Sep  4 2011, 09:51:08) [MSC v.1500 32 bit (Intel)] on win
32
Type "help", "copyright", "credits" or "license" for more information.
>>> import regex
>>> print(regex.search("([\da-f:]+)$", "E", regex.I|regex.V1))
None
>>>

What is the expected output? What do you see instead?
>>> import regex
>>> print(regex.search("([\da-f:]+)$", "E", regex.I|regex.V1))
<_regex.Match object at 0x00C09B10>
>>> print(regex.search("([\da-f:]+)$", "E", regex.I|regex.V1).group(0))
E
>>>

What version of the product are you using? On what operating system?
Windows XP Home SP3 (32-bit version)
Python 3.2.2
regex 0.1.20120112

Please provide any additional information below.
# "e" is ok.
>>> import regex
>>> print(regex.search("([\da-f:]+)$", "e", regex.I|regex.V1))
<_regex.Match object at 0x00C09B10>
>>> print(regex.search("([\da-f:]+)$", "e", regex.I|regex.V1).group(0))
e
>>>

Original issue reported on code.google.com by msm...@gmail.com on 13 Jan 2012 at 11:58

jamadden / mrab-regex-hg

regex.search("([\da-f:]+)$", "E", regex.I|regex.V1) returns None #33