Open Jantonie opened 6 years ago
oh yup,
In order to compare two proportions, we have to build a 2 x 2 contingency table
this would be a 1 x 2 contingency table, yeah?
but there's not really a way you can do this with more than two proportions (with a hypothesis on one of those proportions)? so wouldn't you just do it with a binomial test?
with thanks
jonathon
Currently, with Jamovi, to perform a one-sided significance test for comparing two population proportions, I perform a Chi square test on a 2 x 2 contingency table and I divide the p-value by 2 (see appendix for more detail). Complement_180305.pdf
Sincerely
Jantonie
ah! sorry i misunderstood!
yes, you're right, that would be good to add.
we'll see what we can do.
jonathon
Thank you very much for your answer. Sincerely Jantonie
Hi,
In order to compare two proportions, we have to build a 2 x 2 contingency table with Jamovi. The performed test is a chi-square test that corresponds to a two-sided test (H_1: p_1 \neq p_2). Would it be possible to test a unilateral hypothesis as well (H_1: p_1 < p_2 or H_1: p_1>p_2) as with R (option alternative of prop.test: c(“two.sided”, “less”, “greater”)?
Sincerly