Default cookie filter (domain of the currently displayed page) should be optional

[GoogleCodeExporter]

On http://www.softwareishard.com/blog/firecookie/ one can read "This tab 
displays a list of all cookies associated with domain of the currently 
displayed page."

I'd like to have this "default" filter configurable so that I could switch it 
off and see all cookies saved in a browser. This would allow me (using 
currently available search/filter field in the right upper corner) to see 
cookies associated with different subdomains of a domain of the currently 
displayed page. Let's say ssl.example.com is the domain of the currently 
displayed page but I've been earlier on www.example.com which set some cookies. 
I'd like to see both cookies associated with ssl.example.com and associated 
with www.example.com. Now it's not possible.

What version of the product are you using? On what operating system?
Firecookie 1.1.1, Firebug 1.7X.0a7, Firefox 3.6.12, Windows Vista x64

Original issue reported on code.google.com by p.dobrog...@gmail.com on 28 Nov 2010 at 1:01

[GoogleCodeExporter]

What's the reason to see the cookies of both subdomains when the ones of the 
other domain don't match the current domain?

Firebug just displays contents related to the currently displayed page. Adding 
an option to display all browser cookies doesn't fit into that concept.
Though there is one exception to this: the Persist button. So instead of adding 
a "remove filter" option we should add a button, which persists the list of 
cookies when going to another website similar to what we have inside the Net 
panel.

Please note that Firecookie was integrated into Firebug 1.10a11.

Sebastian

Original comment by sebastia...@gmail.com on 15 Jun 2012 at 11:46

• Changed state: Triaged
• Added labels: cookies, 1.10-a11, Test-case-needed
• Removed labels: Priority-Medium

[GoogleCodeExporter]

Moved to: Issue fbug:5570

Original comment by sebastia...@gmail.com on 15 Jun 2012 at 11:46

• Changed state: Moved