Use two stack to implement a queue, the in_stack is for storing the incoming value, the out_stack is for accessing the first-in value. When we want to mutate the queue, we should check whether the out_stack is empty before or after mutating the queue.
struct MyQueue {
in_stack: Vec<i32>,
out_stack: Vec<i32>
}
/**
* `&self` means the method takes an immutable reference.
* If you need a mutable reference, change it to `&mut self` instead.
*/
impl MyQueue {
fn new() -> Self {
Self {
in_stack: vec![],
out_stack: vec![]
}
}
fn push(&mut self, x: i32) {
if self.out_stack.is_empty() {
self.out_stack.push(x);
} else {
self.in_stack.push(x);
}
}
fn pop(&mut self) -> i32 {
let ret = self.out_stack.pop().unwrap();
if self.out_stack.is_empty() {
while !self.in_stack.is_empty() {
self.out_stack.push(self.in_stack.pop().unwrap());
}
}
ret
}
fn peek(&self) -> i32 {
*self.out_stack.last().unwrap()
}
fn empty(&self) -> bool {
self.in_stack.is_empty() && self.out_stack.is_empty()
}
}
/**
* Your MyQueue object will be instantiated and called as such:
* let obj = MyQueue::new();
* obj.push(x);
* let ret_2: i32 = obj.pop();
* let ret_3: i32 = obj.peek();
* let ret_4: bool = obj.empty();
*/
Practice Dates
Description
Link: https://leetcode.com/problems/implement-queue-using-stacks/description/
Solution
Use two stack to implement a queue, the
in_stack
is for storing the incoming value, theout_stack
is for accessing the first-in value. When we want to mutate the queue, we should check whether theout_stack
is empty before or after mutating the queue.Performance
Time complexity: