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jcrodriguez-dis / moodle-mod_vpl

Virtual Programming Lab for Moodle (Module)
GNU General Public License v3.0
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Job for vpl-jail-system.service failed because a timeout was exceeded #118

Closed ngoquyenbg closed 2 years ago

ngoquyenbg commented 3 years ago

I installed jail server 2.6, and i start service with sudo service vpl-jail-system start -d 8, but It take some time and raise the error message: Job for vpl-jail-system.service failed because a timeout was exceeded. See "systemctl status vpl-jail-system.service" and "journalctl -xe" for details

this is /var/log/syslog: Jan 6 21:21:39 sun vpl-jail-system[19440]: Stopping vpl-jail-system service:
Jan 6 21:21:39 sun systemd[1]: vpl-jail-system.service: Failed with result 'timeout'.
Jan 6 21:21:39 sun systemd[1]: Failed to start VPL Jail System Service.

Please help me to resolve this issue, thank you so much.

jcrodriguez-dis commented 3 years ago

Dear Ngoquyenbg, passing parameters to the start process is deprecated. You must use the LOGLEVEL parameter to increase log level. See https://vpl.dis.ulpgc.es/documentation/vpl-jail-system-2.6.0/configuration.html#loglevel You must report your system details to reproduce the problem.

Best regards, Juan Carlos.