Non numericals in parenthesis don't work.

[Keir-Clyne]

Was trying to emulate the random.choice() function by generating a list and then using the random() number function to generate a number to choose from the list as follows:

list = ["hello", "goodbye", "haha"] a = random(0,2) text = list[a]

but for some reason processing doesn't allow this. Not sure if there is some kind of random.choice() function I'm missing (Although I can't seem to find one)

[tildebyte]

random should work. You should probably post some more info; version of Processing.py, platform... Most importantly, some kind of output giving more detail about the failure ("processing doesn't allow this" is pretty vague).

[Keir-Clyne]

Sorry for the vague answer.

I'm using Processing 3.3.5 with Python mode build 3026

If I use the code:

a = random(0,2)
alist = ["a", "b", "c"]
print(list[a])

The error message I get is:

processing.app.SketchException: TypeError: list indices must be integers
    at jycessing.mode.run.SketchRunner.convertPythonSketchError(SketchRunner.java:248)
    at jycessing.mode.run.SketchRunner.lambda$2(SketchRunner.java:122)
    at java.lang.Thread.run(Thread.java:748)

For some reason processing doesn't allow non-numerical list indicies (So alist[example] where example is not a number).

I'm pretty new to python and processing so not sure if I'm missing something simple but there doesn't seem to be anything in the tutorials about it. Thanks for any information

[jdf]

That's right; array or tuple indexes have to be integers. It wouldn't mean anything to pick the 1.2nd element of a list.

import random

alist = ["a", "b", "c"]
print(random.choice(alist))

[villares]

Hi @Keir-Clyne,

So random(0,2) will produce a float between 0 and 2 (2 not included), then you might want to use int(random(3)) like:

alist = ["a", "b", "c"]
for _ in range(20):
    r = random(3)
    i = int(r)
    choice = alist[i]
    print (r, i, choice)