How to Bind Datetime and customer like Latitude Longitude

[463728946]

var bytes = new byte[]{0x0D,0x74,0x51,0x78,0x43,0x8E,0x6E,0xC4}; //They should be: //Latitude [22.5726840] //Longitude [113.3407940] // //but they are: //Latitude -99.9387581 //Longitude 201.8604045

public class Coordinates { [FieldOrder(0)] [FieldScale(10000000)] [SerializeAs(SerializedType.Int4)] public double Longitude { get; set; } [FieldOrder(1)] [FieldScale(10000000)] [SerializeAs(SerializedType.Int4)] public double Latitude { get; set; } }

[jefffhaynes]

I don’t think the decimal type is supported. I would recommend using float instead.

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From: 463728946 notifications@github.com Sent: Thursday, June 13, 2019 9:18 PM To: jefffhaynes/BinarySerializer Cc: Subscribed Subject: [jefffhaynes/BinarySerializer] How to Bind Datetime and customer like Latitude Longitude (#132)

public class Test { [FieldOrder(0)] [FieldLength(4)] public Datetime UpdateTime {get;set;}

[FieldOrder(1)] [FieldLength(4)] public decimal Latitude { get; set; }

[FieldOrder(2)] [FieldLength(4)] public decimal Longitude { get; set; }

}

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[463728946]

sorry ,I don't get it

[jefffhaynes]

Looks like you're expecting big endian. Try this:

public class Coordinates
{
    [FieldOrder(0)]
    [FieldScale(10000000)]
    [SerializeAs(SerializedType.Int4)]
    [FieldEndianness(Endianness.Big)] 
    public double Longitude { get; set; }

    [FieldOrder(1)]
    [FieldScale(10000000)]
    [SerializeAs(SerializedType.Int4)]
    [FieldEndianness(Endianness.Big)]
    public double Latitude { get; set; }
}

[463728946]

amazing！It's great. thank u so much