jgerity / uspas2016_project3

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Feedback on Version 5 of the Paper #9

Closed cyjwong closed 8 years ago

cyjwong commented 8 years ago

In the paragraph before equation (6), there is a sentence which says that "Therefore, the number of turns N_turns is limited by the selected 10cm horizontal apertures x_max of the bending magnets" I believe 10cm is the aperture of the quads, and it is the quads, not the dipoles, that limit the number of turns.

I wonder if equation 6 is erroneous. From equation where delta_E is the energy loss per turn, and N*delta_E denotes the max. allowed energy loss. This divided by the total E should equal the max. allowed dispersive shift divided by the dispersion function. Hence the modified equation would be of the form: equation

In Table 3, I believe the bending radius and dispersion function of the 1 GeV s.c. case should be 0.33m rather than 0.83m

In the last sentence of the first paragraph in Discussion, it mentions a beam size of sigma_r = 5 micron. I am not sure I understand this correctly, because, according to Table 3, the beam size is at least 500 micron when the electron beam is circling the ring.

ghost commented 8 years ago

Hi Jonathan,

Where did you get this equation from? because in the last version I sent out formula 6 is different. (I got it from Brandon) na_pac_uspas_v5.pdf

Thanks for the bending radius and dispersion, that was indeed a typo.

cyjwong commented 8 years ago

Hi Marlene, I believe formula 6 in the latest version has an error, and the equations I showed are what I thought should be the correct form of formula 6.

The existing formula fails a dimensional analysis. The left hand side, N_turns, is dimensionless, whereas the right hand side has dimension (eV)^-1.

I am sorry for the confusing notation in my initial post. Capital-delta_E was meant to be the energy loss per turn. equation

Perhaps this would be clearer:

x_max - 2*delta-x is the maximum allowed dispersive shift. It should equal the dispersion function times the maximum allowed fractional energy loss. equation The maximum allowed energy loss equals the energy loss per turn times N_turn. equation

Rearranging the terms lead to: equation

ghost commented 8 years ago

you're right, thanks a lot!