Closed ji-0630 closed 1 year ago
SELECT i.REST_ID, i.REST_NAME, i.FOOD_TYPE, i.FAVORITES, i.ADDRESS, r.REVIEW_SCORE
from REST_INFO i inner join
(select REST_ID, round(avg(REVIEW_SCORE), 2) as REVIEW_SCORE
from REST_REVIEW
group by REST_ID) r
on i.REST_ID = r.REST_ID
where i.ADDRESS like "서울%"
order by r.REVIEW_SCORE desc, i.FAVORITES desc
문제 설명