올바른 괄호

[ji-0630]

문제 설명

[ji-0630]

나의 풀이

def solution(s):
    stack = []

    for i in s:
        if i == "(":
            stack.append("(")
        else:
            try: 
                stack.pop()
            except:
                return False
    if len(stack) != 0:
        return False 
    else :
        return True

[ji-0630]

다시 풀기

def solution(s):
    stack = []
    for i in s:
        if i == "(":
            stack.append(i)
        else:
            try:
                stack.pop()
            except:
                return False

    if len(stack) == 0:
        return True
    return False