Open lixcli opened 3 years ago
Hi, I think the original formula which is noted is correct. Here is my demonstrate.
Firstly, the primary formula is
In your formula, because each Wi in |Wi| is independent ,the formula could be transformed into
there is a absolute value in it because
and we can get another formula by a simple demonstrate.
So, the primary formula is correct
Hi, I think the original formula which is noted is correct. Here is my demonstrate.
Firstly, the primary formula is
In your formula, because each Wi in |Wi| is independent ,the formula could be transformed into
there is a absolute value in it because
and we can get another formula by a simple demonstrate.
So, the primary formula is correct