Closed dynaryu closed 1 year ago
Because the states are defined by the travel time, and it takes different times to travel by arc 2 and by arc 1 & 3. The array “times” illustrates the corresponding travel times to each state.
From: Hyeuk Ryu @.> Sent: 31 March 2023 11:41 To: jieunbyun/BNS-JT @.> Cc: Subscribed @.***> Subject: [jieunbyun/BNS-JT] output of fnTrans.doBranch (Issue #9)
For node 5 to 1
Input:
arc_paths = [[2], [1, 3]]
path_times = [0.0901, 0.2401]
unfinished = 0
Output:
branches_surv = [[2], [1, 3], [1], []]
branches_fail = [[], [2], [2, 3], [1, 2]]
states = [1, 2, 3, 3]
times = [0.0901, 0.2401, 100, 100]
Why state of the second case (arc [1, 3] survival, arc [2] failure) becomes 2 not 1? What does 1, 2, and 3 mean as a system for this case?
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What I said last night was some potential issue due to too many states from continuous variable. Alternative approach is binning which converts continous variable to categorical one.
Thanks, I will keep that in mind and think over.
From: Hyeuk Ryu @.> Sent: 06 April 2023 01:34 To: jieunbyun/BNS-JT @.> Cc: Ji-Eun Byun @.>; Comment @.> Subject: Re: [jieunbyun/BNS-JT] output of fnTrans.doBranch (Issue #9)
What I said last night was some potential issue due to too many states from continuous variable. Alternative approach is binning which converts continous variable to categorical one.
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For node 5 to 1
Why state of the second case (arc [1, 3] survival, arc [2] failure) becomes 2 not 1? What does 1, 2, and 3 mean as a system for this case?