Closed endOver closed 4 months ago
设 $f(x)=\left{\begin{array}{ll}\ln \sqrt{x}, & x \geqslant 1, \ 2 x-1, & x<1 .\end{array}\right.$ 求 $f[f(x)]$
设 $f(x)=\left\{\begin{array}{cl}(\cos x)^{\frac{2}{x\arctan x}}, & x \neq 0, \\a, & x=0 .\end{array}\right.$在 $x=0$ 处连续, 则 $a=$
没用转义符吧
所有者
哪个地方没用?
\ 是转义符,写在字符串里 \ 要写作 \\
\
\\
设 $f(x)=\left{\begin{array}{ll}\ln \sqrt{x}, & x \geqslant 1, \ 2 x-1, & x<1 .\end{array}\right.$ 求 $f[f(x)]$
设 $f(x)=\left\{\begin{array}{cl}
(\cos x)^{\frac{2}{x\arctan x}}, & x \neq 0, \\
a, & x=0 .
\end{array}\right.$在 $x=0$ 处连续, 则 $a=$
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