JohnyDL
commented
1 year ago that'd be an interesting addition (or setting), right now I have (several) sets of 37 words that will solve any kilordle in its current state... I'm still looking for a set of 36 or 35 words
But if 4 greens and 1 yellow is an option.... I bet it's possible in less than 26 words. It'd instantly effective to only have one word with J, Q, X, and Z, Z appears in a couple of words twice but pzazz would cover all of them. Q can be twice in qajaq, X twice in xerox and J has 3 options for a double letter and any one would cover all 3, jeuje (covers more Js with qajaq), jujus (covers Us in odd places), hajji, so long as each word covers at least 2 unique letter places and the whole set covers most letters in most places, 26 seems totally doable, it may be that there are other letters that require no complete covering too, bibbs might cover B but maybe paired with kayak, xylyl and yeven with any ly word you'd cover the Ys Ks and make a dent in Ls and Vs, llama would finish the Ls later while valve would fit for Vs with 3 spaces covered and the double possibility, so that's 10 words B, J, K, L Q, V, X, Y and Z, effectively covered A only missing first possition (qajaq or kayak and llama), Es in 3 places (yeven and valve), Us in 2 places (jujus) and M, N, O, P each getting one possition, so on average a touch more than 10 letters covered in 10 words, it might be worth focusing down on words containing F, G, H, W, or completing the M, N, P words leaving C, D, R, S, T till last (assuming that all the vowels would be covered anyway)
example:
flu_d(greens)i(yellow)since the 4 green spots are already taken, the only place for the
iis the 4th letter, seems like as much of a "gimme" as having all the greens