Closed LeoDuhz closed 2 years ago
Although it's implemented in a clever way, the FFT is ultimately just a linear transformation, that is furthermore orthogonal (in the real case) / unitary (complex). So you could write it as a matrix multiplication y = F x where x is the spatial signal, y is the spectral signal, and F is the Fourier matrix. The Jacobian dy/dx of a matrix-vector product function is just the transpose / conjugate transpose of F. Since F is orthogonal/unitary, this equals the ifft.
Although it's implemented in a clever way, the FFT is ultimately just a linear transformation, that is furthermore orthogonal (in the real case) / unitary (complex). So you could write it as a matrix multiplication y = F x where x is the spatial signal, y is the spectral signal, and F is the Fourier matrix. The Jacobian dy/dx of a matrix-vector product function is just the transpose / conjugate transpose of F. Since F is orthogonal/unitary, this equals the ifft.
i understand what you mean, thank you so much for your help!!
Hi,
Thanks for your great work! Your repo really helps me a lot! However, i am encountering some theoretical problems about the derivative of SO(3) fourier transformation when i tries to write the back propagation formula related to SO(3) fourier transformation. To be more specified, if i have
In your code, you write like this:
It seems very intuitive that the partial derivative of SO(3) fft is SO(3) ifft, but i still wonders how you can get this. Can you help to illustrate this in details or is there any paper deriving this formula or discussing about this?
Thanks a lot for your help!!