Closed amdshameer closed 7 years ago
I know that rbd::Jacobian::fullJacobian columns are arranged in the order of rbd::MultiBody::jointPosInDof. Is it the same for CoM Jacobian rbd::CoMJacobian::CoMJacobian
Yes, both jacobians are such that the speed (of the CoM, or an end-effector) can be computed by:
spd = jac * qd
I know that rbd::Jacobian::fullJacobian columns are arranged in the order of rbd::MultiBody::jointPosInDof. Is it the same for CoM Jacobian rbd::CoMJacobian::CoMJacobian