Closed jstolarek closed 7 years ago
Yes, that is strange, the obvious fix seems right to me.
--James
On Feb 22, 2017 9:24 PM, "Jan Stolarek" notifications@github.com wrote:
leq (CBool _) (CBool _) = True leq (CInt i) (CInt j) = i == j leq (CString i) (CString j) = i == j
That case for CBool looks wrong. Why the RHS is True and not b == b'?
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That case for
CBool
looks wrong. Why the RHS isTrue
and notb == b'
?