Open junlon2006 opened 4 years ago
对于有环的:考虑快慢指针,必然会重叠
化零为整:https://leetcode-cn.com/problems/exchange-lcci/comments/
约瑟夫环数学解法:https://leetcode-cn.com/problems/yuan-quan-zhong-zui-hou-sheng-xia-de-shu-zi-lcof/solution/huan-ge-jiao-du-ju-li-jie-jue-yue-se-fu-huan-by-as/
对于有环的:考虑快慢指针,必然会重叠