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juntossomosmais / frontend-dojo

Coding Dojo - Frontend
MIT License
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Entrega dos Desafios #1

Closed mauriciomutte closed 2 years ago

mauriciomutte commented 2 years ago

Um representante do grupo deve postar nos comentários a identificação do seu time e o link do FORK com a resolução dos desafio

Grupo [NOME_DO_GRUPO] ​

1 - [INSERIR_CODIGO_AQUI] ​ 2 - [INSERIR_CODIGO_AQUI] ​ 3 - [INSERIR_CODIGO_AQUI]

Natalie9 commented 2 years ago

https://github.com/Natalie9/frontend-dojo Grupo Powerpuff Girls 1 - Natalie Tolentino 2 - Giulia Tondin 3 - Mayara Alencar

1 - https://github.com/Natalie9/frontend-dojo/blob/main/challenge-1.js 2 - https://github.com/Natalie9/frontend-dojo/blob/main/challenge-2.js 3 - https://github.com/Natalie9/frontend-dojo/blob/main/challenge-3.js

rbalves commented 2 years ago

Grupo Rafael/Denilson/Eduardo

1 - https://github.com/rbalves/frontend-dojo/blob/main/challenge-1.js

// Desafio 1: FizzBuzz

function fizzBuzz(number) {
  const list = Array.from({length: number}, (_, i) => i + 1)

  return list.map(number => {
    if (number % 3 === 0 && number % 5 === 0) {
      return "FizzBuzz"
    }

    if (number % 3 === 0) {
      return "Fizz"
    }

    if (number % 5 === 0) {
      return "Buzz"
    }

    return String(number)
  })
}

console.log(fizzBuzz(15));
// ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

2 - https://github.com/rbalves/frontend-dojo/blob/main/challenge-2.js


// Desafio 2: Palindrome

function normalizeString(word) {
  return word
    .toLowerCase()
    .replace(/ /g, "")
    .replace(/[^\w ]/g, "");
}

function isPalindrome(word) {
  const solution = normalizeString([...word].reverse().join(""));

  const originalWord = normalizeString(word);

  return solution === originalWord;
}

console.log(isPalindrome("civic")); // true
console.log(isPalindrome("race a car")); // false
console.log(isPalindrome("A man, a plan, a canal: Panama")); // true

3 - https://github.com/rbalves/frontend-dojo/blob/main/challenge-3.js

// Desafio 3: Duplicate

function duplicateCount(text) {
  const formatedText = [...text.toLowerCase()];

  const duplicates = formatedText.filter(
    (item, index) => formatedText.indexOf(item) !== index
  );

  return {
    duplicados: duplicates.length,
    caracteres: duplicates,
  };
}

console.log(duplicateCount("abcde")); // {duplicados: 0, caracteres: []}
console.log(duplicateCount("abcdea")); // {duplicados: 1, caracteres: ['a']}
console.log(duplicateCount("aabBcde")); // {duplicados: 2, caracteres: ['a', 'b']}
console.log(duplicateCount("aA11")); // {duplicados: 2, caracteres: ['a', 1]}
rafaelgslima commented 2 years ago

Grupo Alone in the dark

Godinho, Bomfas e Pedro

1- function fizzBuzz(numbers) {
  let result = []
  for (let number = 1; number <= numbers; number++) {
    const divisionThree = number % 3 === 0
    const divisionFive = number % 5 === 0
    if(divisionThree && divisionFive) {
      result.push('FizzBuzz')
    } else if (divisionThree) {
      result.push('Fizz')
    } else if (divisionFive) {
      result.push('Buzz')
    } else {
      result.push(number)
    }
  }
  return result
}
console.log(fizzBuzz(15));
2 - function isPalindrome(word) {
  const regexCleanEspecialCaracter = /[^a-z0-9]/gi
  const stringClean = word.toLowerCase().replace(regexCleanEspecialCaracter, '')
  const arrayOfWord = stringClean.split('')
  const arrayOfWordReverse = arrayOfWord.reverse()
  const resultString = arrayOfWordReverse.join('')
  return resultString === stringClean
}
console.log(isPalindrome("civic")); // true
console.log(isPalindrome("race a car")); // false
console.log(isPalindrome("A man, a plan, a canal: Panama")); // true
RodrigoRVSN commented 2 years ago

Grupo A(Rodrigo Victor, Lucas Gomes)

1- 

// Desafio 1: FizzBuzz

function getValue(number) {
  if (number % 3 === 0 && number % 5 === 0) return 'FizzBuzz'
  if (number % 3 === 0) return 'Fizz'
  if (number % 5 === 0) return 'Buzz'
  return String(number)
}

function fizzBuzz(number) {
  const list = []

  for (let i = 1; i <= number; i++) {
    const value = getValue(i)
    list.push(value)
  }

  return list
}

console.log(fizzBuzz(15));
// ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

2- 

// Desafio 2: Palindrome

function isPalindrome(word) {
  const nonLetters = /[^a-zA-Z]+/g
  const filteredWord = word.replace(nonLetters, '').toLowerCase()
  const splittedWord = filteredWord.split('').reverse().join('')

  if (splittedWord === filteredWord) {
    return true
  }

  return false
}

console.log(isPalindrome("civic")); // true
console.log(isPalindrome("race a car")); // false
console.log(isPalindrome("A man, a plan, a canal: Panama")); // true

3- 

// Desafio 3: Duplicate

function convertIntIfIsNumber(value) {
  if (isNaN(value)) {
    return value
  }

  return parseInt(value)
}

function duplicateCount(text) {
  const splittedText = text.toLowerCase().split('')
  const alreadyHas = {}
  const duplicatedItems = []

  for (let i = 0; i < splittedText.length; i++) {
    if (alreadyHas[splittedText[i]]) {
      const value = convertIntIfIsNumber(splittedText[i])
      duplicatedItems.push(value)
    }

    alreadyHas[splittedText[i]] = true
  }

  return {
    duplicados: duplicatedItems.length,
    caracteres: duplicatedItems
  }
}

console.log(duplicateCount("abcde")); // {duplicados: 0, caracteres: []}
console.log(duplicateCount("abcdea")); // {duplicados: 1, caracteres: ['a']}
console.log(duplicateCount("aabBcde")); // {duplicados: 2, caracteres: ['a', 'b']}
console.log(duplicateCount("aA11")); // {duplicados: 2, caracteres: ['a', 1]}
jowjow22 commented 2 years ago

Grupo squirrels 1-

function fizzBuzz(number) {
  if(number % 3 === 0 && number % 5 === 0) {
    return 'FizzBuzz';
  }
  else if(number % 3 === 0) {
    return 'Fizz';
  }
  else if(number % 5 === 0) {
    return 'Buzz';
  }
  return number
}

function createList(times){
  if(!times || typeof times !== 'number') return "Querendo quebrar meu código amigão?"

  return Array.from({length: times}, (_unused, index) => fizzBuzz(index + 1))
}

console.log(createList(15));

2 - 

function isPalindrome(word) {
  if(!word || typeof word !== 'string') return "Brinca mais que a brincadeira hein"

  const formatedWord = word.toLowerCase().replace(/[^a-z]/g, '');
  const reversed = formatedWord.split('').reverse().join('');
  return formatedWord === reversed;
}

console.log(isPalindrome("civic")); // true
console.log(isPalindrome("race a car")); // false
console.log(isPalindrome("A man, a plan, a canal: Panama")); // true

3 - 

function duplicateCount(text) {
  if(!text || typeof text !== 'string') return "Querendo quebrar meu código amigão?"
  const formatedText = text.toLowerCase().replace(/[^a-z0-9]/g, '');
  const duplicates = formatedText.split('').filter((char, index) => formatedText.indexOf(char) !== index);
  return {
    duplicados: duplicates.length,
    caracteres: duplicates
  };
}
console.log(duplicateCount("abcde")); // {duplicados: 0, caracteres: []}
console.log(duplicateCount("abcdea")); // {duplicados: 1, caracteres: ['a']}
console.log(duplicateCount("aabBcde")); // {duplicados: 2, caracteres: ['a', 'b']}
console.log(duplicateCount("aA11")); // {duplicados: 2, caracteres: ['a', 1]}
munyrasirio commented 2 years ago

console.log('Grupo')

1- 

function fizzBuzz(number) {
  const newArr = []
  for (let index = 1; index <= number; index++) {
    if (index % 15 === 0) {
      newArr.push('FizzBuzz')
    } else if (index % 3 === 0) {
      newArr.push('Fizz')
    } else if (index % 5 === 0) {
      newArr.push('Buzz')
    } else {
      newArr.push(index)
    }
  }
  return newArr;
}
console.log(fizzBuzz(15));

2-

function isPalindrome(word) {
  const normalString = word.toLowerCase().replaceAll(/[^a-zA-Z]/g, "");
  let reverseString = ''
  for(let i = normalString.length - 1; i >= 0; i--) {
    reverseString += normalString[i]
  }
  return reverseString === normalString
}
console.log(isPalindrome("civic")); // true
console.log(isPalindrome("race a car")); // false
console.log(isPalindrome("A man, a plan, a canal: Panama")); // true

3- N/A

deverebor commented 2 years ago

Um representante do grupo deve postar nos comentários a identificação do seu time e o link do FORK com a resolução dos desafio

Grupo Lucas & Igor no Multiverso da Juntos

1 - Desafio 1 2 - Desafio 2 3 - Não concluida

ldantas-s commented 2 years ago

Equipe D

1 - 

const dividedBy = (divisor, divisivel) => divisivel % divisor === 0;

function fizzBuzz(number) {
  const fizz = [];

  if (number < 1) return [];

  for (let i = 1; i <= number; i++) {
    let value = i;
    const divisibleByThree = dividedBy(3, i);
    const divisibleByFive = dividedBy(5, i);

    if (divisibleByThree) value = 'Fizz';
    if (divisibleByFive) value = 'Buzz';
    if (divisibleByThree && divisibleByFive) value = 'FizzBuzz';

    fizz.push(value);
  }

  return fizz;
}

2 - [INSERIR_CODIGO_AQUI] ​ 3 - [INSERIR_CODIGO_AQUI]

userAugustos commented 2 years ago

Grupo: Sei lá, achei esse desafio e fiz. https://github.com/userAugustos/frontend-dojo

  1. Challenge-1

    function fizzBuzz(number) {
    const arr = [...Array(number).keys()].map(n => ++n).map(n => {
        let number

        number = n % 3 ? n : 'Fizz'
        number = n % 5 ? number : 'Buzz'
        number = (n % 3 || n % 5) ? number : 'FizzBuzz'

        return number
        })

        return arr
    }

console.log(JSON.stringify(fizzBuzz(15)));

  2. Challenge-2

    function isPalindrome(word) {
const cleanWord = word.replace(/[^\wèéòàùì]/g, '').toLowerCase();
let compareWord = '';

// could be done with split().reverse().join(), but i think for is more fun now
for (let i = cleanWord.length - 1; i >=0; i--) {
    compareWord += cleanWord[i]
}

return compareWord === cleanWord
}
console.log(isPalindrome("civic")); // true
console.log(isPalindrome("race a car")); // false
console.log(isPalindrome("A man, a plan, a canal: Panama")) // true

  3. Challenge-3

    
function duplicateCount(text) {
const arr = text.toLowerCase().split('')
let valuesSoFar = Object.create(null)
let caracteres = []

for (let i = 0; i < arr.length; i++) {
    if(valuesSoFar[arr[i]]){
        caracteres.push(arr[i])
    }
    valuesSoFar[arr[i]] = true
}

return {
    duplicados: **caracteres**.length,
    caracteres
}
}

console.log(duplicateCount("abcde")); // {duplicados: 0, caracteres: []} console.log(duplicateCount("abcdea")); // {duplicados: 1, caracteres: ['a']} console.log(duplicateCount("aabBcde")); // {duplicados: 2, caracteres: ['a', 'b']} console.log(duplicateCount("aA11")); // {duplicados: 2, caracteres: ['a', 1]}