Open junxnone opened 1 year ago
$\huge h(x)=kd^{-1}(x)\int{-\infty}^{+\infty}\int_{-\infty}^{+\infty}f(\xi)c(\xi,x)d\xi$
$\huge c(\xi,x)=e^{-\frac{1}{2}(\frac{d(\xi,x)}{\sigma_d})^2}$
$\huge h(x)=kr^{-1}(x)\int{-\infty}^{+\infty}\int_{-\infty}^{+\infty}f(\xi)s(f(\xi),f(x))d\xi$
$\huge s(\xi,x)=e^{-\frac{1}{2}(\frac{\delta(f(\xi),f(x))}{\sigma_r})^2}$
$\huge \delta(\phi,\textbf{f}) = \delta(\phi - \textbf{f}) = \left|\phi - \textbf{f}\right|$
void cv::bilateralFilter(InputArray src, OutputArray dst, int d, double sigmaColor, double sigmaSpace, int borderType = BORDER_DEFAULT )
Bilateral Filter 双边滤波
原理
Domain Filter (Geometric)
$\huge h(x)=kd^{-1}(x)\int{-\infty}^{+\infty}\int_{-\infty}^{+\infty}f(\xi)c(\xi,x)d\xi$
$\huge c(\xi,x)=e^{-\frac{1}{2}(\frac{d(\xi,x)}{\sigma_d})^2}$
Range Filter (Photometric)
$\huge h(x)=kr^{-1}(x)\int{-\infty}^{+\infty}\int_{-\infty}^{+\infty}f(\xi)s(f(\xi),f(x))d\xi$
$\huge s(\xi,x)=e^{-\frac{1}{2}(\frac{\delta(f(\xi),f(x))}{\sigma_r})^2}$
$\huge \delta(\phi,\textbf{f}) = \delta(\phi - \textbf{f}) = \left|\phi - \textbf{f}\right|$
不同 $σ_d$ 和 $σ_r$ 效果
Tips
OpenCV API
Reference