Closed drewburns closed 2 years ago
Hey there, I am following the Pokemon tutorial posted by Justin - with the same dataset and code on Lambda Labs with a 1x A100 (40 GB SXM4).
1x A100 (40 GB SXM4)
I download the checkpoint sd-v1-4-full-ema.ckpt into the correct folder and run
sd-v1-4-full-ema.ckpt
python main.py -t --base configs/stable-diffusion/pokemon.yaml --gpus 0, --scale_lr False --num_nodes 1 --check_val_every_n_epoch 10 --finetune_from models/ldm/stable-diffusion-v1/sd-v1-4-full-ema.ckpt
I run into an issue Any idea why it is failing here? I install the requirements.py so the versions should all be up to date?
It appears to be this line: image_transforms.extend([transforms.ToTensor(), transforms.Lambda(lambda x: rearrange(x * 2. - 1., 'c h w -> h w c'))])
image_transforms.extend([transforms.ToTensor(), transforms.Lambda(lambda x: rearrange(x * 2. - 1., 'c h w -> h w c'))])
rank_zero_warn( Epoch 0: 0%| | 0/209 [00:00<00:00, 5907.47it/s]Summoning checkpoint. Traceback (most recent call last): File "main.py", line 901, in <module> trainer.fit(model, data) File "/home/ubuntu/stable-diffusion/ldm/data/simple.py", line 137, in <lambda> transforms.Lambda(lambda x: rearrange(x * 2. - 1., 'c h w -> h w c'))]) ..... AttributeError: module 'keras.backend' has no attribute 'is_tensor' ```
Works with pip install --upgrade keras
pip install --upgrade keras
Hey there, I am following the Pokemon tutorial posted by Justin - with the same dataset and code on Lambda Labs with a
1x A100 (40 GB SXM4)
.I download the checkpoint
sd-v1-4-full-ema.ckpt
into the correct folder and runpython main.py -t --base configs/stable-diffusion/pokemon.yaml --gpus 0, --scale_lr False --num_nodes 1 --check_val_every_n_epoch 10 --finetune_from models/ldm/stable-diffusion-v1/sd-v1-4-full-ema.ckpt
I run into an issue Any idea why it is failing here? I install the requirements.py so the versions should all be up to date?
It appears to be this line:
image_transforms.extend([transforms.ToTensor(), transforms.Lambda(lambda x: rearrange(x * 2. - 1., 'c h w -> h w c'))])