pjax Update

[loveorigami]

How update form after formSubmit?

[loveorigami]

$('#createCompany').on('kbModalSubmit', function(event, data, status, xhr) { console.log('kbModalSubmit'); // You may call pjax reloads here });

I think, better

$('#createCompany').on('kbModalSubmit', function(event, data, status, xhr) {
    console.log('kbModalSubmit');
    if (status) {
       // You may call pjax reloads here
   }
});

and need add line

status = false

in https://github.com/karnbrockgmbh/yii2-modal-ajax/blob/master/assets/js/kb-modal-ajax.js#L160

[loveorigami]

here my code

<?php
use yii\widgets\Pjax;

$this->registerJs(
    "$('#add-author-lib_id').on('kbModalSubmit', function(event, data, status, xhr) {
        console.log('kbModalSubmit' + status);
        if(status){
            $.pjax.reload({container:'#author-create'});  //Reload Form
        }
    });"
);
?>
<div class="author-create">
    <?php Pjax::begin([
        'id' => 'author-create',
        'timeout' => 100000
    ]); ?>
    <?php echo $this->render('_form', [
        'model' => $model
    ]) ?>
<?php Pjax::end(); ?>

</div>

but after submit in bootstrap - form is not reloaded by pjax (((...

[loveorigami]

I am did better ) In controller

            if (Yii::$app->request->isAjax) {
                // JSON response is expected in case of successful save
                Yii::$app->response->format = \yii\web\Response::FORMAT_JSON;
                return [
                    'success' => true,
                    'id' => $model->id,
                    'name' => $model->name,
                ];
            }

In view

$('#createCompany').on('kbModalSubmit', function(event, data, status, xhr) {
    console.log('kbModalSubmit' + status);
    if(status){
        $(this).modal('toggle');
        $('#createCompany-select').append($('<option></option>').attr('value', data['id']).prop("selected","selected").text(data['name']));
    }
});