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kdschlosser / samsungctl

Remote control Samsung televisions via a TCP/IP connection
MIT License
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Unhandled Response Samsung TV #139

Open monnarr opened 3 years ago

monnarr commented 3 years ago

Hello if I want to give the TV a command, I get a message on TV were I have to accept a foreign controller. But I got this error in my command prompt Traceback (most recent call last): File "C:\Program Files\Python39\Scripts\samsungctl-script.py", line 33, in sys.exit(load_entry_point('samsungctl==0.8.0b0', 'console_scripts', 'samsungctl')()) File "C:\Program Files\Python39\lib\site-packages\samsungctl-0.8.0b0-py3.9.egg\samsungctl__main.py", line 355, in main with Remote(config) as remote: File "C:\Program Files\Python39\lib\site-packages\samsungctl-0.8.0b0-py3.9.egg\samsungctl\remote.py", line 67, in enter__ self.open() File "C:\Program Files\Python39\lib\site-packages\samsungctl-0.8.0b0-py3.9.egg\samsungctl\utils.py", line 24, in wrapper return func(*args, *kwargs) File "C:\Program Files\Python39\lib\site-packages\samsungctl-0.8.0b0-py3.9.egg\samsungctl\remote_legacy.py", line 95, in open self._read_response(True) File "C:\Program Files\Python39\lib\site-packages\samsungctl-0.8.0b0-py3.9.egg\samsungctl\utils.py", line 24, in wrapper return func(args, **kwargs) File "C:\Program Files\Python39\lib\site-packages\samsungctl-0.8.0b0-py3.9.egg\samsungctl\remote_legacy.py", line 156, in _read_response raise exceptions.UnhandledResponse(response) samsungctl.exceptions.UnhandledResponse: <exception str() failed>

Can someone help?

ToasterDEV commented 2 years ago

I can attest to having the exact same issue, here is my traceback:

$ samsungctl --host 192.168.1.7 --name myremote KEY_VOLDOWN
Traceback (most recent call last):
  File "/home/toasterdev/miniconda3/bin/samsungctl", line 33, in <module>
    sys.exit(load_entry_point('samsungctl==0.8.0b0', 'console_scripts', 'samsungctl')())
  File "/home/toasterdev/miniconda3/lib/python3.9/site-packages/samsungctl-0.8.0b0-py3.9.egg/samsungctl/__main__.py", line 355, in main
    with Remote(config) as remote:
  File "/home/toasterdev/miniconda3/lib/python3.9/site-packages/samsungctl-0.8.0b0-py3.9.egg/samsungctl/remote.py", line 67, in __enter__
    self.open()
  File "/home/toasterdev/miniconda3/lib/python3.9/site-packages/samsungctl-0.8.0b0-py3.9.egg/samsungctl/utils.py", line 24, in wrapper
    return func(*args, **kwargs)
  File "/home/toasterdev/miniconda3/lib/python3.9/site-packages/samsungctl-0.8.0b0-py3.9.egg/samsungctl/remote_legacy.py", line 95, in open
    self._read_response(True)
  File "/home/toasterdev/miniconda3/lib/python3.9/site-packages/samsungctl-0.8.0b0-py3.9.egg/samsungctl/utils.py", line 24, in wrapper
    return func(*args, **kwargs)
  File "/home/toasterdev/miniconda3/lib/python3.9/site-packages/samsungctl-0.8.0b0-py3.9.egg/samsungctl/remote_legacy.py", line 156, in _read_response
    raise exceptions.UnhandledResponse(response)
samsungctl.exceptions.UnhandledResponse: <exception str() failed>

The TV prompts for permission to allow "myremote" to control it, but after that nothing happens.

Thanks for the help!