Open kejhy93 opened 2 months ago
To download a ZIP file from the internet and extract it in-memory (i.e., without saving it to the file system), you can achieve this by following these steps:
ZipInputStream
to read and extract the contents.Here’s a solution using Spring Boot and Java standard libraries for handling the process entirely in memory.
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RestController;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.URL;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
@RestController
public class ZipInMemoryController {
@GetMapping("/download-and-extract-inmemory")
public String downloadAndExtractInMemory() {
// URL of the ZIP file
String zipFileUrl = "https://example.com/sample.zip"; // Replace with actual URL
try {
// 1. Download ZIP file as InputStream
InputStream zipInputStream = downloadZipFileAsStream(zipFileUrl);
// 2. Extract the ZIP file in-memory
extractZipInMemory(zipInputStream);
return "ZIP file downloaded and extracted in-memory successfully!";
} catch (IOException e) {
e.printStackTrace();
return "Failed to download or extract the ZIP file in-memory.";
}
}
// Method to download the ZIP file as an InputStream
private InputStream downloadZipFileAsStream(String zipFileUrl) throws IOException {
URL url = new URL(zipFileUrl);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("GET");
connection.setDoOutput(true);
connection.connect();
return connection.getInputStream();
}
// Method to extract the ZIP file in-memory
private void extractZipInMemory(InputStream inputStream) throws IOException {
try (ZipInputStream zipInputStream = new ZipInputStream(inputStream)) {
ZipEntry entry;
while ((entry = zipInputStream.getNextEntry()) != null) {
System.out.println("Extracting: " + entry.getName());
// If the entry is a file, read the content
if (!entry.isDirectory()) {
ByteArrayOutputStream fileOutputStream = new ByteArrayOutputStream();
byte[] buffer = new byte[1024];
int length;
while ((length = zipInputStream.read(buffer)) > 0) {
fileOutputStream.write(buffer, 0, length);
}
// Here you have the file content in memory as a byte array
byte[] fileContent = fileOutputStream.toByteArray();
System.out.println("File size: " + fileContent.length + " bytes");
// You can now handle the file content as needed (e.g., store in database, process, etc.)
}
zipInputStream.closeEntry();
}
}
}
}
Downloading the ZIP file:
downloadZipFileAsStream
method uses HttpURLConnection
to download the ZIP file from the internet and returns an InputStream
.Extracting ZIP in memory:
ZipInputStream
is used to process the ZIP file stream.ZipEntry
is processed in-memory (read directly from the ZipInputStream
without writing to disk).ByteArrayOutputStream
, which keeps the file contents in memory as a byte array.Processing the files:
You can use this approach when working with ZIP files stored on the internet that need to be downloaded and processed without touching the filesystem.
To download a ZIP file using a Spring Boot application, you typically need to:
Here is a step-by-step guide:
1. Add Required Dependencies
First, make sure you have the necessary dependencies for a Spring Boot web application in your
pom.xml
(for Maven) orbuild.gradle
(for Gradle).2. Create a REST Controller
In the controller, you will create a method that:
Explanation:
3. Test the Endpoint
Start your Spring Boot application and navigate to
http://localhost:8080/download-zip
. This will download the ZIP file withfile1.txt
andfile2.txt
inside it.If you're running this on a different port, make sure to adjust the URL accordingly.